设长方体的棱长别离为x、y、z,则有xy=根3,yz=根5,xz=根15解得x^2=3,y^2=1,z^2=5而外接球的曲径为长方体的对角线D^2=9,S=πD^2=9π
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设长方体的棱长别离为x、y、z,则有xy=根3,yz=根5,xz=根15解得x^2=3,y^2=1,z^2=5而外接球的曲径为长方体的对角线D^2=9,S=πD^2=9π