20am 1次方b2m 4次方bm 2次方)除以4am次方bm 1次方等于?
a^(3m)=2
b^(2m)=3
[a^(2m)]^3+[b^m]^6
=[a^(3m)]^2+[b^2m]^3
=2^2+3^3
=4+9
=13
“-(A的2次方B )的3次方×BM的值救”(如若,您对我的回答称心,请点击左下角“好评”,谢谢您的摘纳。)
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a^(3m)=2
b^(2m)=3
[a^(2m)]^3+[b^m]^6
=[a^(3m)]^2+[b^2m]^3
=2^2+3^3
=4+9
=13
“-(A的2次方B )的3次方×BM的值救”(如若,您对我的回答称心,请点击左下角“好评”,谢谢您的摘纳。)