有一台两线造压力变送器,量程为0~1mpa,对应输出电流为4~20mA,试求(1)压力P与输出电流I的关系表达式(2)计算当P=0.5mpa 0.8mpa 1mpa时压力变送器的输出电流
X/Y*16 4
X:其时的展现值
Y:量程
16:20MA-4MA
4:基数4MA
如0.5MPA时,0.5/1*16 4=12MA
如0.8MPA时,0.8/1*16 4=16.8MA
如1MPA时,1/1*16 4=20MA
0
X/Y*16 4
X:其时的展现值
Y:量程
16:20MA-4MA
4:基数4MA
如0.5MPA时,0.5/1*16 4=12MA
如0.8MPA时,0.8/1*16 4=16.8MA
如1MPA时,1/1*16 4=20MA